x^2-2x+60=x^2+3x-20

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Solution for x^2-2x+60=x^2+3x-20 equation: 



x^2-2x+60=x^2+3x-20

We move all terms to the left:

x^2-2x+60-(x^2+3x-20)=0

We get rid of parentheses

x^2-x^2-2x-3x+20+60=0

We add all the numbers together, and all the variables

-5x+80=0

We move all terms containing x to the left, all other terms to the right

-5x=-80

x=-80/-5

x=+16

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